50m^2+225m+63=0

Solution for 50m^2+225m+63=0 equation:

50m^2+225m+63=0

a = 50; b = 225; c = +63;
Δ = b2-4ac
Δ = 2252-4·50·63
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38025}=195$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(225)-195}{2*50}=\frac{-420}{100}
=-4+1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(225)+195}{2*50}=\frac{-30}{100}
=-3/10
$